For what concentration of ag+ will the emf
WebAnswer Explain how rusting of iron is envisaged as setting up of an electrochemical cell. 243 Views Answer Calculate the emf of the cell in which the following reaction takes place: Ni (s) + 2Ag+ (0.002 M) Ni2+ (0.160 M) + 2Ag (s) Given that 1585 Views Answer Advertisement Company Careers Terms of Use Privacy Policy Sitemap Feedback Help CLAT WebCalculate the emf of the cell in which the following reaction takes place: Ni (s) + 2Ag+ (0.002 M) Ni2+ (0.160 M) + 2Ag (s) Given that 1585 Views Answer The molar conductivity of 0.025 mol L –1 methanoic acid is 46.1 S cm2 mol–1. Calculate its degree of dissociation and dissociation constant.
For what concentration of ag+ will the emf
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WebFeb 2, 2016 · A This is a concentration cell, in which the electrode compartments contain the same redox active substance but at different concentrations. ... [Ag+] in the two cells. … WebDec 11, 2024 · Eº (Cu 2+ /Cu) and Eº (Ag + /Ag) is +0.337 V and +0.799 V respectively. Make a cell whose EMF is +ve. If the concentration of Cu 2+ is 0.01M and Ecell at 25ºC …
WebThe concentrations of Ag + at which the e.m.f. of the cell is zero at equimolar concentration of Fe 2+ and Fe 3+. Write answer as nearest integer after multiplying it with 10. Given E Ag +/Ago =0.80V and E Fe 3+/Fe 2+o =0.77V Hard Solution Verified by Toppr Correct option is A) WebMar 8, 2024 · The cell diagram implies that we are under standard conditions where we have unit concentration which is then increased by a factor of 10. You should be given the E∘ values: Cu2+ +2e ⇌ Cu × × × xE∘ = + 0.34xV Ag+ + e ⇌ Ag × × × ×E∘ = +0.8xV The Cu ∣ Cu2+ half cell has the least +ve value so this will shift right to left and give out electrons.
WebGiven E Ag+ / Ag = + 0.8 V, ENi +2 / Ni = – 0.25 V. Which of the following statements is true ? ... Find the EMF of cell formed by connecting two half cells: Pt(s) MnO -4 (0.1 M) ; MnCl2 (0.2 M) HCl (1M) ... For strong as well as weak electrolyte conductivity increases with the concentration of solute but equivalent conductivity of the ... WebApr 14, 2024 · A 12.5% (w/w) NiCl (129.61 g/mol) solution has a density of 1.149 g/mL. Calculate (a) the molar concentration of NiCl, in this solution. (b) the molar Clº concentration of the solution. (c) the mass in grams of NiCl, contained in each liter of this...
WebAssertion. For the reaction ; A(g)⇌B(g)+C(g),K p=1 atm. If we start with equal moles of all gases at 9 atm of initial pressure, then at equilibrium partial pressure of A increases. …
WebMar 5, 2024 · The standard reduction potential of Cu 2+ /Cu and AG + /AG electrodes are 0.337 and 0.799V respectively. construct a galvanic cell using these electrodes so that … el solar beach clubWebDec 10, 2024 · The electromotive force (EMF) is the maximum potential difference between two electrodes of a galvanic or voltaic cell. ... A concentration of 1 M in an ideal solution is defined as the standard condition, ... {Ag \rightarrow Ag+ + e^-}\hspace{15px} E^* = … Electrochemistry Skills Expected in Quiz. Explain the meaning of terms used in … ford folding tonneau cover f150WebSep 16, 2024 · सेल का emf ( Note – Full form of emf is Electro-Motive Force ) E 0 सेल = E 0 दायाँ – E 0 बायाँ. E 0 सेल = E 0 cathode – E 0 anode. E 0 सेल = E 0 Cu 2+ /Cu – E 0 Zn 2+ /Zn = +0.34 – (- 0.76) = +0.34 + 0.76. E … el software se puede tocarWebsilver ammine complexRelated. sam duluk married. silver ammine complex ford folding truck bed coverWebEmf of an electrochemical cell; Unknown ionic concentrations; The pH of solutions and solubility of sparingly soluble salts can be measured with the help of the Nernst equation. Limitations of Nernst Equation. The … ford folding in halfWebMar 8, 2024 · sf(E_(cell)=+0.49color(white)(x)V) The cell diagram implies that we are under standard conditions where we have unit concentration which is then increased by a … el sol baytown txWebFeb 4, 2024 · The concentration of can be determined by using the solubility concept. Given ionic solid is ; The Equilibrium Equation for the ionic compound will be: ⇄ + Now, the solubility product () of the ionic compound will be; Given that; the concentration is ; & solubility product of the given ionic solid is ∴ = = 2.97560008 × 10⁻¹⁰ ≅ ford focus zx3 wheels